Question

Identify the axis of symmetry and vertex of f(x) = –x2 –2x–1.

Axis of symmetry: x = 1; Vertex: (– 1, –1)
Axis of symmetry: x = 1; Vertex: (1, 0)
Axis of symmetry: x = – 1; Vertex: ( 1, 0)
Axis of symmetry: x = – 1; Vertex: (– 1, 0)

Answer 1

@freckles @welshfella

Answer 2

@mckenzieandjesus you still here?

Answer 3

yes

Answer 4

transform the function to vertex form which is

a(x - b)^2 + c

wher the vertex is (b,c) and the axis of symmetry is y = -b

Answer 5

`or` use the formula \[\huge\rm \frac{ -b }{ 2a }\] to find x coordinate of the vertex
then substitute x for its value into the original equation to find y-coordinate of the vertex
and x coordinate of the vertex would be the axis of symmetry

Answer 6

what numbers would i put in that formula?

Answer 7

\[\huge\rm Ax^2+Bx+C\]
a= leading coefficient
b-middle term
c=constant

Answer 8

please tag username we aren't getting notification :(