Question

log(2)6•log(6)8

Answer 1

is i log(6)2 •log(6)8
base 6 ??

Answer 2

No the first one is base two in the second one is base six

Answer 3

\[\huge\rm log_2 6 \times \log_6 8\] like this

Answer 4

*and

Answer 5

Yes you got it

Answer 6

How do you solve it

Answer 7

@Nnesha

Answer 8

@PhantomCrow

Answer 9

@Michele_Laino

Answer 10

alright familiar the the change of base formula ?

Answer 11

hey ??

Answer 12

huh anywys i have to go
chage of base formula
\[\huge\rm \log_\color{ReD}{b} \color{blue}{a} =\frac{ \log \color{blue }{a} }{ log\color{ReD}{ b} }\]
write both log in fraction ^by using change of base formula

Answer 13

then rewrite 8 in terms of base 2

Answer 14

make sense ?? @carolinar7

Answer 15

i'll do the log(6)8 \[\huge\rm \log_\color{ReD}{6} \color{blue}{8} =\frac{ \log \color{blue }{8} }{ log\color{ReD}{ 6} }\]
rewrite 8 in terms of base 2
2 times 2 times 2 = 8 you can write it as 2^3
\[\large\rm \log_\color{ReD}{6} \color{blue}{8} =\frac{ \log \color{blue }{2^3} }{ log\color{ReD}{ 6} }\]
apply the power rule
power rule \[\large\rm log_b x^y = y \log_b x\]
write log(2) 6 in fraction by using change of base formula.
that's it