Question

Describe how to prepare 1.00 L of 0.646 M HCl solution, starting with 2.00 M HCl solution.

Answer 1

It's been a while but I think it may be this:

\[M_{1}V_{1} = M_{2}V_{2}\]


\[\frac{ M_{1}V_{1} }{ M_{2} } = V_{2}\]

\[\frac{ 1.0L*0.646M }{ 2.00M } = 0.323 L \]

we would need 323 mL of a 2.0M solution


@Rushwr your help is needed
@Shikamaru11 my good friend thoughts?

Answer 2

well @Photon336 Sir this rite no doubt :)

Answer 3

@Photon336 Absolutely correct :) Dude u are awesome at chemistry.

Answer 4

Hmm...

Answer 5

Yep, diluted with water to 1 L