Question

Can anyone help? The link is a picture of the problem.
http://oi62.tinypic.com/2lbjmv9.jpg

Answer 1

@matt101

Answer 2

during 2, there is a displacement of 15m for 0.5 hr
velocity = displacement / time

do the same for segment -3

Answer 3

So 30 m/s for v2 and 25 for v3?

Answer 4

umm thats in km/h you have to convert it to m/s

Answer 5

3.0 x 10^3

Answer 6

v2=30 v3=3000? That doesn't make sense.

Answer 7

I'm pretty sure I'm not doing this right.

Answer 8

Sorry openstudy is messing up for me.

Answer 9

Hello?

Answer 10

you have to convert km -> m and also hrs -> seconds

so 1km/h = 1000/3600 m/s

Answer 11

So it's v3=.277?

Answer 12

I'm getting confused could you work out the problem?

Answer 13

I'm confused and running short on time and I have another problem to work. Sorry.

Answer 14

Velocity is the change in position divided by the change in time. Change in anything is the final value minus the initial value of that thing

So for interval #2, the change in position is 30 - 15 = 15 km, which is 15 000 m, and the change in time is 1.5 - 1 = 0.5 hours, which is 1800 seconds.

The average velocity of interval #2 is therefore 15 000 / 1800 = 8.33 m/s

Now you try the same process for #3!

Answer 15

I got 1.85 for #3

Answer 16

Looks good!