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Five people want to rent the last two copies of a movie. How many ways can these five people rent the two movies? A. 10 B. 9 C. 8 D. 7 E. 6
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Take 5 people and group them into two groups, one of size 2 (the ones that get the copies) and the other of size 3 (the ones that don't get the copies): $$ {{5}\choose{2}}=\cfrac{5!}{2!3!} $$ This is because there are 5! ways to permute the 5 people, but 2! of them are the same combination, just in different order and similarly for the 3! of the second group. Does this make sense?
ohh i get it now so the answer is 10?
yes!
The answer is, "A". 10.
whoops he already answered you. Sorry!
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