Graph the data in the table below. Which kind of function best models the data? Write an equation to model the data.
quadratic; y = –x2 + 2x – 3
linear; y = – 2x – 3
exponential; y = –3•1.5x
quadratic; y = –x2 – 3
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OpenStudy (mckenzieandjesus):
|dw:1444433891025:dw|
OpenStudy (mckenzieandjesus):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
what do you have so far (in terms of work)?
OpenStudy (mckenzieandjesus):
I dont understand how to do it
jimthompson5910 (jim_thompson5910):
ok let's say we pick on choice B
linear; y = – 2x – 3
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jimthompson5910 (jim_thompson5910):
IF the answer was choice B, then (0,-3) should lie on the graph
so should (1,-2) and (2,-3) etc etc
jimthompson5910 (jim_thompson5910):
but what is the value of y when x = 1
y = – 2x – 3
y = -2*1 - 3
y = ??
OpenStudy (mckenzieandjesus):
-5?
jimthompson5910 (jim_thompson5910):
yes so (1,-5) is actually on y = – 2x – 3
not (1,-2)
jimthompson5910 (jim_thompson5910):
this eliminates choice B
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OpenStudy (mckenzieandjesus):
ok
jimthompson5910 (jim_thompson5910):
test the points with the other equations. You need to make sure all points fit
OpenStudy (mckenzieandjesus):
so would i do -2*2-3?
OpenStudy (mckenzieandjesus):
nvrm!
jimthompson5910 (jim_thompson5910):
well you could, but we proved B wasn't the answer. So there's no need to check B any more
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OpenStudy (mckenzieandjesus):
got it nvrm lol
jimthompson5910 (jim_thompson5910):
alright
OpenStudy (mckenzieandjesus):
Would the answer be A?
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (mckenzieandjesus):
Thank You!. I never understood those but now I do. A lot simpler than I thought.