Question

4) What is the height of the apple when your friend catches it?
(**HINT: The height would be the y-coordinate of the highest point.)

Double click on the space below to show your work.

h(t) = -16t^2 + 38.4t + 0.96

h= height t= time (seconds)

I will fan and medal for work plus answers!

Answer 1

How do I find the height? How do I switch the equation to find the height instead of the time? I can solve it just not sure how to set it up.

Answer 2

there is more to this question right?

Answer 3

like more words

Answer 4

Make t=0. :)

Answer 5

The information is enough. :)

Answer 6

naw dude its asking for the vertex

Answer 7

Would I just substitute the time that we just figured out into the equation? The 2.4 seconds?

Answer 8

No you don't have to. Just make t=0. :)

\(h(t) = -16(0)2 + 38.4(0) + 0.96\)

Answer 9

why would you do that?? is the friend .96 ft off the ground

Answer 10

The height we're finding is the same thing as the vertex. =_= Notice that the vertex in this case is the maximum because \(a\) is a negative.

Answer 11

no not for t=0

Answer 12

t=o is your initial starting point not the vertex

Answer 13

or your y-intercept

Answer 14

If (0,y) <--- this is the vertex. Please stop misguiding the one who asked.

Answer 15

NO IT ISNT...

Answer 16

If you solve the equation mathway gave me, I got 0.96.

Answer 17

b/2a is the x coordinate and f(b/2a) is your Y

Answer 18

"(**HINT: The height would be the y-coordinate of the highest point.)"

Which means that you need to find the y-coordinate.

Answer 19

Yes, it is \(\huge 0.96\). :)

Answer 20

MAX HIGHT WHICH IS THE Y OF YOUR VERTEX

Answer 21

t=0 is not a vertex

Answer 22

that is 0 time e=meaning the apple hasnt been thrown yet...

Answer 23

It is not a vertex because it is PART OF THE VERTEX. It is the x-intercept.

Answer 24

how can your friend catch something that hasnt been thrown?

Answer 25

@Nnesha Please confirm this.

Answer 26

no x intercept is finding the root dude...

Answer 27

you're really off

Answer 28

@pooja195

Answer 29

The question I posted before this was asking if a person threw an apple how many seconds would it take to reach the other person 3 stories up? We solved and got 2.4 seconds.

Answer 30

yes

Answer 31

Show me how you will find the height then. You keep on complaining, but you're not showing any work.

Answer 32

Of course it is correct. I was the one who helped her. :P

Answer 33

`(**HINT: The height would be the y-coordinate of the highest point.)`

Answer 34

but now plug that number into the function

Answer 35

that is the hight

Answer 36

not t=0...

Answer 37

@mathway im not calling you dumb people make mistakes and this is one of yours

Answer 38

You would still get the same answer either way, 0.96.

Answer 39

yes buy he cant say thats what it is you have to explain it in the context of the problem

Answer 40

since its a root ofcourse it would cancle out the other 2 but in a 4th power polynomial that would fail miserably

Answer 41

so the fundamental way to explain the answer is V = {(b/2a),f(b/2a)} and you look for Y

Answer 42

Okay guys last question!
Using the same equation - h(t) = -16t^2 + 38.4t + 0.96
With h = height and t = time in seconds
5) Suppose your friend does not catch the apple and it falls back to the ground. How long did it take the apple to hit the ground?
(**HINT: When the apple hits the ground is when the graph hits the x-axis.)

Answer 43

find the root

Answer 44

calm plz
use the hint
highest point = max
so we need y -coordinate of the max point (max=vertex)

Answer 45

lol sorry for late reply >.< internet iz very slow -.-

Answer 46

lol its ok

Answer 47

ok hold up go back what did you get for your sec for the apple to get to him??????!!!!

Answer 48

the kid on the 3rd floor????

Answer 49

x coordinate of the vertex can be any number
(0,y) = y-intercept :=)

Answer 50

\[\frac{ -38.4 \pm \sqrt{38.4^{2}-4(-16)(0.96)} }{ 2(-16) }\]

Answer 51

yea lol but only if it is centered on the orgin would that be a vertex

Answer 52

yea @tbull1221 that works

Answer 53

what does that give you?

Answer 54

\[\frac{ -38.4 \pm \sqrt{1536} }{ -32 }\]

Answer 55

Then you get:
\[\frac{ -38.4 \pm 16\sqrt{6} }{ -32 }\]

Answer 56

"x coordinate of the vertex can be any number
(0,y) = y-intercept :=)"

@Nnesha

Thank you for backing up! At least I know that I'm not dumb and I don't necessarily have to say irrelevant things when I made a mistake. :)