Question

Find the average value of f(x) = sin(x) over the interval [0, π].

Answer 1

https://gyazo.com/d975c3d9750e0048a4741d5d7ead2c04

Answer 2

@jim_thompson5910

Answer 3

M = average value of f(x) from x = a to x = b

\[\Large M = \frac{1}{b-a}\int_{a}^{b}f(x)dx\]

Answer 4

In this case,
a = 0
b = pi
f(x) = sin(x)


\[\Large M = \frac{1}{b-a}\int_{a}^{b}f(x)dx\]
\[\Large M = \frac{1}{\pi-0}\int_{0}^{\pi}\sin(x)dx\]
\[\Large M = ??\]

Answer 5

That's basically what I did without multiplying by 1/pi

Answer 6

So it should be 2/pi

Answer 7

you are correct