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If a spring is oscillating (moving) according to the velocity equation v(t) = sin(t) (in ft/s), then what is its displacement over its first π seconds of travel?
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@jim_thompson5910
All I did was plug in pi, which seems extremely wrong.
Maybe plug pi into the integral?
the displacement is equal to the area under the velocity curve
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so you just need to evaluate \[\Large \int_{0}^{\pi}\sin(t)dt\]
Final answer is 2?
yeah
displacement = velocity * time
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