Question

For an object whose velocity in ft/sec is given by v(t) = cos(t), what is its distance, in feet, travelled on the interval t = 1 to t = 5?

Answer 1

@jim_thompson5910

Answer 2

\[\int\limits_{1}^{5} \cos(t) dt\]

Answer 3

Solve that ^

Answer 4

what did you get

Answer 5

careful, you need to put absolute value for "distance"

Answer 6

yeah

Answer 7

1.8

Answer 8

good point, or break up the interval into smaller pieces

Answer 9

find the area under the curve

Answer 10

So......1.8 it is

Answer 11

And dan please give chris his maple syrup

Answer 12

@Ephemera what a lad

Answer 13

@chris00 no man deserves to live without his syrup.

Answer 14

should be around 2.2..

Answer 15

2.2?

Answer 16

Seriously?

Answer 17

i just graphed it...lel

Answer 18

Let's see what @jim_thompson5910 has to say.