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Mathematics 14 Online
OpenStudy (anonymous):

Simple derivative question.

OpenStudy (anonymous):

OpenStudy (anonymous):

I assume you implicitly differentiate and substitute in x=0 ? You'll just have an equation in terms of y then? Or am I doing something wrong?

zepdrix (zepdrix):

Yah that's strange, seems like they would want you to evaluate this at some particular y'(x,y) since it's going to depend on both variables :d weird

zepdrix (zepdrix):

But ya that sounds right, implicit, then 0 all your x's, and simplify Getting stuck on differentiating any of the pieces? :o

OpenStudy (anonymous):

No I can differentiate it find. Just stuck on the actual understanding of the question.

OpenStudy (anonymous):

Possible to get the y value maybe?

zepdrix (zepdrix):

Oh oh yes, it looks like we can get the y-coordinate that corresponds to x=0 from the original expression!

zepdrix (zepdrix):

I think so at least, it looks like a lot of stuff is going to cancel out.

OpenStudy (anonymous):

Really? Well we then get ln(y)+y=y/2 right?

zepdrix (zepdrix):

y/1 on the right side

OpenStudy (anonymous):

oooooooooooo. The y's cancel.

zepdrix (zepdrix):

ooo they so sneaky :D

OpenStudy (anonymous):

oooooooooooo. The y's cancel.

OpenStudy (anonymous):

Wow that's clever :P .

OpenStudy (anonymous):

Thanks!

zepdrix (zepdrix):

\c:/

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