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OpenStudy (anonymous):
Simple derivative question.
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OpenStudy (anonymous):
OpenStudy (anonymous):
I assume you implicitly differentiate and substitute in x=0 ? You'll just have an equation in terms of y then?
Or am I doing something wrong?
zepdrix (zepdrix):
Yah that's strange, seems like they would want you to evaluate this at some particular y'(x,y) since it's going to depend on both variables :d weird
zepdrix (zepdrix):
But ya that sounds right,
implicit, then 0 all your x's, and simplify
Getting stuck on differentiating any of the pieces? :o
OpenStudy (anonymous):
No I can differentiate it find. Just stuck on the actual understanding of the question.
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OpenStudy (anonymous):
Possible to get the y value maybe?
zepdrix (zepdrix):
Oh oh yes, it looks like we can get the y-coordinate that corresponds to x=0 from the original expression!
zepdrix (zepdrix):
I think so at least, it looks like a lot of stuff is going to cancel out.
OpenStudy (anonymous):
Really? Well we then get ln(y)+y=y/2 right?
zepdrix (zepdrix):
y/1 on the right side
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OpenStudy (anonymous):
oooooooooooo. The y's cancel.
zepdrix (zepdrix):
ooo they so sneaky :D
OpenStudy (anonymous):
oooooooooooo. The y's cancel.
OpenStudy (anonymous):
Wow that's clever :P .
OpenStudy (anonymous):
Thanks!
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zepdrix (zepdrix):
\c:/
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