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Mathematics 16 Online
OpenStudy (en):

PLEASE HELP! WILL MEDAL AND FAN! If y = tan(x+π), find x as a function of y.

OpenStudy (anonymous):

just use inverse rules?

OpenStudy (anonymous):

arctan(y)=x+k*pi x=-k*pi +arctan(y) but -pi and +pi are pretty much the same so we usually take the positive value x=k*pi + arctan(y)

OpenStudy (anonymous):

i think thats all to it. perhaps look for asymptotes?

OpenStudy (en):

My book says that the answer is x= pi + Arctan y. can u explain the inverse rules?

OpenStudy (anonymous):

pretty much the rule with inverse trig is that \[\sin (\arcsin x) = x ; \tan(arctanx)=x; \cos(\arccos(x)=x\]

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