Question

A jet fighter, initially at rest, is launched from an aircraft carrier. it reaches a speed of 49m/sat the end of the catapult and this requires 3 seconds. Assuming the acceleration is constant, Whats is the length of the deck that the plane moves across?

Answer 1

lets begin by listing our knowns and unknowns. we know that the plane accelerates from 0m/s to 49 m/s in 3 seconds. so to find its acceleration all we need to do is assume that every second it will reach a third of the way to 49m/s. so we need to devide 49/3 to find the accelleration. the equation for this is \[a=\frac{ v-u }{ t }\] (u) being the initial velocity which is 0. now that we have the acceleration we can substiitute it into our next equation to find the distance. \[s=ut+1/2at ^{2}\] time is 3seconds as given in the question. so it accelerates at 49/3=16.33m/s/s put this value into the equation above as (a)

Answer 2

I got 73.48m/s
am I right?

Answer 3

s=ut or 0 + 1/2(16.33)(3)^2

Answer 4

was that what your working looked like?

Answer 5

Yes.

Answer 6

then it is correct

Answer 7

(= thanks