Question

hhhlll

Answer 1

@YoungStudier @Nnesha @PrincessHush @pooja195

Answer 2

PLEASE! NEED HELP

Answer 3

@surjithayer

Answer 4

\[h=ut+\frac{ 1 }{ 2 }g t^2\]
for each initial velocity u=0 m/s

Answer 5

\[g ~t^2=2h,g=\frac{ 2h }{ t^2 }\]

Answer 6

h is height
t=time taken
g=acceleration due to gravity

Answer 7

@surjithayer What is the acceleration due to gravity for the Earth, Moon, and Mars?

Answer 8

would t= 6.6 for the first empty slot?

Answer 9

distance m=height=h
Time T=t
i solve first
\[g=\frac{ 2*2.25 }{ \left( 0.680 \right)^2 }=?\]

Answer 10

9.7

Answer 11

9.732

Answer 12

d = 1/2at2 is the equation for an object that starts at rest.

Answer 13

ok so- that is the one for the first box?

Answer 14

what would I do for the second box going horizontal?

Answer 15

when the body falls from a certain height,initial velocity=0 m/s

Answer 16

So what how would I figure out acceleration due to gravity for the second box going across?

Answer 17

h=3.08,t=0.793

Answer 18

so I would use that to figure out the second box?? @surjithayer

Answer 19

first two values are for earth
next two for Moon and last two for Mars.

Answer 20

so the very first box on the graph is 9.732 right???

Answer 21

@surjithayer

Answer 22

correct

Answer 23

@surjithayer

Answer 24

please help with the rest

Answer 25

Hm