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Mathematics 15 Online
OpenStudy (anonymous):

Help

OpenStudy (anonymous):

@Michele_Laino

OpenStudy (michele_laino):

starting from inequality: \(8<2b\) I can divide both sides by \(2\) so I can write this: \[\frac{8}{2} < \frac{{2b}}{2}\] please simplify

OpenStudy (anonymous):

How? :3

OpenStudy (michele_laino):

what is 8:2=...?

OpenStudy (anonymous):

what does ":" mean?

OpenStudy (michele_laino):

I mean 8 divided by 2

OpenStudy (anonymous):

4

OpenStudy (michele_laino):

ok! now, what is 2/2=...?

OpenStudy (anonymous):

1

OpenStudy (michele_laino):

ok! so that inequlity is equivalent to this one: \(4<b\), which caqn be rewritten as below: \(b>4\)

OpenStudy (michele_laino):

inequality*

OpenStudy (anonymous):

so then that would be it?

OpenStudy (michele_laino):

oops.. can*

OpenStudy (michele_laino):

please wait, we have to rewrite the second your inequality: \(2b+15<5\)

OpenStudy (anonymous):

Oh

OpenStudy (michele_laino):

If I subtract 15 to both sides I get: \(2b+15-15<5-15\) please simplify

OpenStudy (anonymous):

How would I simplify that?

OpenStudy (texaschic101):

keep in mind...since there are no equal signs in your inequalities, that means that the circles are open....that will automatically eliminate 2 of them

OpenStudy (michele_laino):

what is: 15-15=...? and what is 5-15=...?

OpenStudy (anonymous):

0 and -10?

OpenStudy (michele_laino):

ok!

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

what do you do with the 2b?

OpenStudy (michele_laino):

so we get: \(2b<-10\) now I divide both sides by 2, so I write this: \[\frac{{2b}}{2} < \frac{{ - 10}}{2}\]

OpenStudy (michele_laino):

what is 2/2=...? and what is -10/2=...?

OpenStudy (michele_laino):

hint: we get \(b<-5\)

OpenStudy (michele_laino):

so your set is represented by these inequalities: \(b>4\) \(or\) \(b<-5\)

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