Question

A gas undergoes a process such that the ratio of P and V is constant and equal to one. What's the molar heat capacity?

Answer 1

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Answer 2

\[C_{m} = \frac{\partial q }{\partial T}\]Is this relation right?

Answer 3

MATH PROCESSING ERROR

Answer 4

That drawing isn't important. Just a PV graph with slope one.

Answer 5

\[q = \Delta U - w\]\[= \frac{3}2RT + pV = \frac{3}{2}RT + RT =\frac{5}{2}RT\]

Answer 6

I don't think it's 5R/2 though.

Answer 7

Looks like I nowhere used the fact that \(p=V\).

Answer 8

I suspect \(w=\int p(t)V(t)\,dt=\int p(t)^2\,dt\).

Answer 9

Oh, what a stupid mistake.

Answer 10

\[\frac{pV}{2}=\frac{p^2}{2}= \frac{V^2}{2}\]

Answer 11

well duh

Answer 12

then we're done here.

Answer 13

Why?

Answer 14

WHY IS MATH NOT PROCESSING

Answer 15

\(TEST\)

Answer 16

WTF

Answer 17

just refresh

Answer 18

K NOW IT IS BACK

Answer 19

So the answer is 3/2R?

Answer 20

No. 2R.