Mathematics
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OpenStudy (calculusxy):
MEDAL!!!
Question will be posted below.
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OpenStudy (calculusxy):
\[\huge v^2 - 20 = 0 \]
OpenStudy (calculusxy):
Solve with quadratic formula
Nnesha (nnesha):
ok have you tried anything yet ?
OpenStudy (calculusxy):
yes gimme a moment
Nnesha (nnesha):
okay
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OpenStudy (anonymous):
\[\frac{ -b \pm \sqrt{b^2-4ac}}{ 2a } \]
OpenStudy (calculusxy):
\[\frac{ -0 \pm \sqrt{0 - 4(-20)} }{ 2 }\]
OpenStudy (anonymous):
yes
OpenStudy (calculusxy):
i thought the new equation would be like:
\[v^2 + 0a - 20 = 0\]
OpenStudy (calculusxy):
\[\frac{ -0 \pm 8.9 }{ 2 }\]
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OpenStudy (anonymous):
0v would be better, but yes. v^2 +0v -20 = 0
Nnesha (nnesha):
v^2 -20 is same as `v^2 -0v -20`
Nnesha (nnesha):
well would be great if get the final answer in radical
Nnesha (nnesha):
don't take square of 20
factor it out
Nnesha (nnesha):
square root*
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OpenStudy (calculusxy):
the answer key for this in decimal form...
Nnesha (nnesha):
oh okay then.
OpenStudy (calculusxy):
\[\frac{ -0 \pm 8.9 }{ 2 } = 4.45 \]
OpenStudy (anonymous):
remember it's \[\pm \]
OpenStudy (calculusxy):
okay so -4.45 or 4.45
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OpenStudy (anonymous):
yes
Nnesha (nnesha):
^ye right it's \[\rm a \pm b ~= a-b ~~ and ~a+b\]
OpenStudy (calculusxy):
is my answer correct?
OpenStudy (anonymous):
yes it is. if your key says 4.4721... it's only because you cut off some decimals from 8.9
Nnesha (nnesha):
i didn't get 4.4 `5`
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OpenStudy (anonymous):
but you did solve it correctly.
OpenStudy (calculusxy):
ok thank you :)