I
@zepdrix @triciaal
I need to know the acceleration due to gravity and the average G value for each of them given what I have
E Earth Moon Mars Distance (m) 2.25 3.08 4.04 4.57 4.68 3.55 Time (s) 0.680 0.793 2.20 2.26 1.58 1.38 Acceleration due to Gravity (m/s^2) 9.732 9.795 1.669 1.789 3.749 3.728 Average G value for the location (m/s^2)
I NEED TO KNOW THE AVERAGE G VALUE FOR THE LOCATION
I need the equation or formula please I am confused
a picture of the chart/table will work better methinks but the acceleration could be obtained from the slope I'd think
and average... is more or less rate of change, which brings us back to slope again
Earth Moon Mars Distance (m) 2.25 3.08 4.04 4.57 4.68 3.55 Time (s) 0.680 0.793 2.20 2.26 1.58 1.38 Acceleration due to Gravity (m/s^2) 9.732 9.795 1.669 1.789 3.749 3.728 Average G value for the location (m/s^2)
then again, a picture of the table woiuld help :)
This is the chart but it looks a little messed up but it is in line
well, surely doesn't look like that on your screen... so just screenshot it methink
I'm on a macbook
but I will try
Here it is
it is a download did you get it
http://prntscr.com/8q0dt3 There's a screenshot if you can't download the document for some strange reason. For future reference, press command + shift + 4 to screenshot something on a Mac.
yes.... well you have two values per each location so the average "G"ravity will be the sum of both, divided by 2 say for earth will be \(\bf \cfrac{9.732+9.795}{2}\)
So would they be in order= 14.6295 2.5635 5.613
@jdoe0001
@jdoe0001 Please check
@triciaal Did i do the table right?? :-)
no idea haven't look yet
@triciaal could you check please
not sure of final for each location same process velocity = distance /time acceleration = velocity/time for Earth (3.08 - 2.25)/ (0.793-0.680) = velocity velocity/time(1) = 9.732 velocity/time(2) = 9.795 average G = velocity/(t2 - t1)
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