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Mathematics 11 Online
OpenStudy (iwanttogotostanford):

I

OpenStudy (iwanttogotostanford):

@zepdrix @triciaal

OpenStudy (iwanttogotostanford):

I need to know the acceleration due to gravity and the average G value for each of them given what I have

OpenStudy (iwanttogotostanford):

E Earth Moon Mars Distance (m) 2.25 3.08 4.04 4.57 4.68 3.55 Time (s) 0.680 0.793 2.20 2.26 1.58 1.38 Acceleration due to Gravity (m/s^2) 9.732 9.795 1.669 1.789 3.749 3.728 Average G value for the location (m/s^2)

OpenStudy (iwanttogotostanford):

I NEED TO KNOW THE AVERAGE G VALUE FOR THE LOCATION

OpenStudy (iwanttogotostanford):

I need the equation or formula please I am confused

OpenStudy (jdoe0001):

a picture of the chart/table will work better methinks but the acceleration could be obtained from the slope I'd think

OpenStudy (jdoe0001):

and average... is more or less rate of change, which brings us back to slope again

OpenStudy (iwanttogotostanford):

Earth Moon Mars Distance (m) 2.25 3.08 4.04 4.57 4.68 3.55 Time (s) 0.680 0.793 2.20 2.26 1.58 1.38 Acceleration due to Gravity (m/s^2) 9.732 9.795 1.669 1.789 3.749 3.728 Average G value for the location (m/s^2)

OpenStudy (jdoe0001):

then again, a picture of the table woiuld help :)

OpenStudy (iwanttogotostanford):

This is the chart but it looks a little messed up but it is in line

OpenStudy (jdoe0001):

well, surely doesn't look like that on your screen... so just screenshot it methink

OpenStudy (iwanttogotostanford):

I'm on a macbook

OpenStudy (iwanttogotostanford):

but I will try

OpenStudy (iwanttogotostanford):

OpenStudy (iwanttogotostanford):

Here it is

OpenStudy (iwanttogotostanford):

it is a download did you get it

OpenStudy (anonymous):

http://prntscr.com/8q0dt3 There's a screenshot if you can't download the document for some strange reason. For future reference, press command + shift + 4 to screenshot something on a Mac.

OpenStudy (jdoe0001):

yes.... well you have two values per each location so the average "G"ravity will be the sum of both, divided by 2 say for earth will be \(\bf \cfrac{9.732+9.795}{2}\)

OpenStudy (iwanttogotostanford):

So would they be in order= 14.6295 2.5635 5.613

OpenStudy (iwanttogotostanford):

@jdoe0001

OpenStudy (iwanttogotostanford):

@jdoe0001 Please check

OpenStudy (iwanttogotostanford):

@triciaal Did i do the table right?? :-)

OpenStudy (triciaal):

no idea haven't look yet

OpenStudy (iwanttogotostanford):

@triciaal could you check please

OpenStudy (triciaal):

not sure of final for each location same process velocity = distance /time acceleration = velocity/time for Earth (3.08 - 2.25)/ (0.793-0.680) = velocity velocity/time(1) = 9.732 velocity/time(2) = 9.795 average G = velocity/(t2 - t1)

OpenStudy (triciaal):

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