Question

I'm having a hard time remembering how to go about this problem. help? Problem below

Answer 1

\[\frac{ 4}{ 8 }^{2}b+\frac{ 40 }{ 32 }^{3}b\]

Answer 2

@Nnesha ?

Answer 3

well the variables are the same so they are like terms
combine them

Answer 4

here is an example
when the variables and the exponents are the same we can add/subtract their coefficients
\[\rm 2x^2+5x^2 = (2+5)x^2=7x^2\]

Answer 5

\[\frac{ 44}{ 40 }^{3}b ?????\]

Answer 6

hmm we didn't add them correctly :=)
\[\rm \frac{ 4}{ 8 }^{2}b+\frac{ 40 }{ 32 }^{3}b=(\frac{4^2}{8}+\frac{40^3}{32})b\]

Answer 7

that seems too simple though.. lol

Answer 8

\[\rm \frac{ 4}{ 8 }^{2}b+\frac{ 40 }{ 32 }^{3}b=(\frac{4^2}{8}+\frac{40^3}{32})b\]
\[\rm (\color{ReD}{\frac{4^2}{8}+\frac{40^3}{32}})b\]
solve paretheses
what's the common denominator ??

Answer 9

do we add the exponents?

Answer 10

I'm so confused

Answer 11

no when we `multiply` same bases then we should add their exponents
when we combine like terms base stay the same we just have to add/subtract their `coefficients `

Answer 12

I'm still getting \[\frac{ 44 }{ 40 }^{3}b\] ..........

Answer 13

alright show some work
i mean what was your step how did you get 40 at the denominaotr ?

Answer 14

i see what you did there common mistake

Answer 15

I just added 8 and 32... is that wrong?

Answer 16

\[\frac{ 3 }{ 2} + \frac{4}{6}\] wrong that's not how we should add