A box has 60 balls, of which 22 are red, 19 are blue, and 19 are yellow, as before. Balls are extracted at random but this time not returned to the box. What is the probability that after performing this test three times exactly two are blue and one is red?

Question

A box has 60 balls, of which 22 are red, 19 are blue, and 19 are yellow, as before.   Balls are extracted at random but this time not returned to the box.   What is the probability that after performing this test three times exactly two are blue and one is red?

anonymous · Answer

when i do the calculation i got the answer 1818/17110 but the book answer have 5643/17110, i think i did something wrong my calculation

anonymous · Answer

this what i did to get the calculation $$\frac{  \left(\begin{matrix}19 \ 2\end{matrix}\right)* \left(\begin{matrix}22 \ 1\end{matrix}\right)*\left(\begin{matrix}19 \ 0\end{matrix}\right)}{ \left(\begin{matrix}60 \ 3\end{matrix}\right)}$$

amistre64 · Answer

what is the test being performed?

anonymous · Answer

combination

amistre64 · Answer

What is the probability that after performing ***this test*** three times exactly two are blue and one is red?

the questions feels like its missing information ... prolly from a different question?

anonymous · Answer

k 
A box has 50 balls, of which 16 are red, 19 are blue, and 15 are yellow.   Balls are extracted at random then returned to the box.   What is the probability that after performing this test three times exactly two are yellow and one is blue?

anonymous · Answer

similar but a bit different w/ a number

amistre64 · Answer

experiment ... might be a better word

anonymous · Answer

i see

amistre64 · Answer

A box has 60 balls, of which 22 are red, 19 are blue, and 19 are yellow, as before. Balls are extracted at random but this time not returned to the box. 

What is the probability that after performing this (process) three times exactly two are blue and one is red?

rbb
brb
bbr

3*(22.19.18)/(60.59.58)

maybe?

anonymous · Answer

doing that the number will be large

amistre64 · Answer

1881/17110 is what that turns out to be

amistre64 · Answer

P(bbr) or P(brb) or P(rbb)

are the only ways we can pull 2bs and 1r in 3 pulls  right?

anonymous · Answer

correct

amistre64 · Answer

and after we pull them out the remaining amounts decrease by 1

22 for red,  19 and 18 for blues

and the ball count reduces  60,59,58  for the product of the denominator ...

anonymous · Answer

is like this |dw:1444575916412:dw|