Log Question:
\[\log _{10} 1/\sqrt{10}\]
Sqrt 10/ 10 is wrong :(
\[\log_{10} \frac{1}{\sqrt{10}}\] like this ?
Change of base: \(\log_a (x) =\dfrac{\log_b (x)}{\log_b (a)}\)
Oh yes! Lol
you can convert square root to an exponent if you want or use change of base formula
log(a/b)=log a-log b so the given expression becomes log 1-log sqrt 10 =-log sqrt 10 =-log (10)^1/2=-1/2
Lets take \(x=\dfrac{1}{\sqrt{10}}\)
\[\sqrt{y} \] can be written as \[\rm y^\frac{ 1 }{ 2 }\] so \[\rm \log_{10} \frac{ 1 }{ (10)^\frac{ 1 }{ 2 } }\] move the (10)^/2 at the numerator
So it would be \[\log 1/\sqrt{10} /\log 10\] ??
Oh oh okay
\[\begin{align} \log_{10} \left(\frac{1}{\sqrt{10}}\right) &=\frac{\log\left(\frac{1}{\sqrt{10}}\right)}{\log(10)}\\& = \frac{\log(1)-\log(\sqrt{10})}{\log(10)} \\&=\frac{-\frac{1}{2}\log(10)}{\log(10)}\\&=-\frac{1}{2} \end{align}\]
Wow thanks for all the support :o
typo (10)^{1/2} remember the exponent rule when move base from the numerator to denominator sign of the exponent would change \[\huge\rm \frac{ 1 }{ x^{-m }}= x^m\]
Yes oh my gosh thank you @Nnesha
u already got the answer so i'm just gonna work itout \[\log_{10} 10^{-\frac{1}{2}}\] apply the power rule power rule \[\large\rm log_b x^y = y \log_b x\] \[-\frac{1}{2} \log_{10}10\] log_{10} 10 = 1 so left wth -1/2
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