Question

I got the answer, I just dont know how. LOG help :(

Answer 1

here to help m8

Answer 2

\[e^x-5=(1/e^4)^x+2\]

Answer 3

the x+2 is in the exponent with the x :/ Lol thanks

Answer 4

u should see if tiger algebra will give the answer

Answer 5

My teacher said something about how a power and power cancel, and her next step was this \[e=e^-4(x+2)\]

Answer 6

just sayin retipe it here if u can and i will solve

Answer 7

retype

Answer 8

Whats tiger algebra?

Answer 9

this is the website
tiger-algebra.com

Answer 10

type in your browser

Answer 11

I have the answer, just dont know how

Answer 12

and post ypur answer

Answer 13

your

Answer 14

didi u do it

Answer 15

that website will show u the steps too m8

Answer 16

It cant do what I needed :/

Answer 17

damn what do u need m8

Answer 18

sorry im part russian german and african american so im good in some things most i cant really do

Answer 19

is this ur question \[\huge\rm e^{x-5}=(\frac{1}{e^4})^{x+2}\] @Melissa_Something

Answer 20

i don't know if the left side is e^{x-5} or e^(x) - 5

Answer 21

but right side you can move e^4 to the numerator just like we did on the previous post

Answer 22

is this ur question \[\huge\rm e^{x-5}=(\frac{1}{e^4})^{x+2}\]

`OR`
\[\huge\rm e^x-5 =(\frac{1}{e^4})^{(x+2)}\]

Answer 23

here is an example \[\huge\rm \frac{1}{x^{-m}}= x^{m}\]
when we flip the fraction sign of the exponent would change
so \[\frac{1}{e^{4}}=?\]

Answer 24

and yes `e` and `ln` cancel each other out \[\large\rm e^{\ln x} = x\]
\[\large\rm \cancel{e^{\ln} x} = x\]