Question

If 5.00ml of 0.314M KOH is diluted to exactly 125mL with water, what is the concentration of the resulting solution?

Answer 1

It's a dilution, \(\sf M_1V_1=M_2V_2\)

\(\sf (0.314~M)*(5~mL)=M_2*(5~mL+125~mL)\)

the final molarity is \(\sf M_2\)

Answer 2

@aaronq isn't it diluted to a total volume of 125 mL, not 125 mL added?

Answer 3

oh right, sorry, i read the question as "diluted with exactly"

Answer 4

so subtract 5 from 125?

Answer 5

125 mL is the final volume,

\(\sf (0.314~M)*(5~mL)=M_2*125~mL)\)

Answer 6

ok looks like it works out correct into what the possible answers could be. Thank you again.

Answer 7

np!