If 5.00ml of 0.314M KOH is diluted to exactly 125mL with water, what is the concentration of the resulting solution?

Question

aaronq · Answer

It's a dilution, $\sf  M_1V_1=M_2V_2$

$\sf (0.314~M)*(5~mL)=M_2*(5~mL+125~mL)$

the final molarity is $\sf  M_2$

whpalmer4 · Answer

@aaronq isn't it diluted to a total volume of 125 mL, not 125 mL added?

aaronq · Answer

oh right, sorry, i read the question as "diluted with exactly"

anonymous · Answer

so subtract 5 from 125?

aaronq · Answer

125 mL is the final volume,

$\sf (0.314~M)*(5~mL)=M_2*125~mL)$

anonymous · Answer

ok looks like it works out correct into what the possible answers could be.  Thank you again.

aaronq · Answer

np!