Question

Find the Derivative
P(t) = 2*e^(-2e)^(2t)

P prime (t) =

Answer 1

By using the chain rule we get\[P'(t)=2e^{(-2e)^{2t}}*-2e^{2t}*2\]

It's a tedious one, but if you take it slow and break it down and it's not too bad. Chain rules within chain rules are always annoying

Answer 2

yeah, it marked it as wrong ^^^^^

Answer 3

Interesting.

Answer 4

If the exponent is `really` (-2t)^(2t),
then this one is going to be be a lil more frustrating since the -2 is included lol

Answer 5

yeah ^

Answer 6

would we make a substitution?
\[u=-2e ^{2t}\]

Answer 7

See that's different than what you initially wrote :P

Answer 8

\[\large\rm y=a^x\]Recall that for differentiating exponentials:\[\large\rm y'=a^x(\ln a)\]So then,\[\large\rm \frac{d}{dt}(-2e)^{2t}=(-2e)^{2t}\cdot \ln(-2e)\cdot (2)\]Oh but then log of -2e isn't defined...
Yah having a negative base is uhh... no bueno :U hmm

Answer 9

yeaah, see i tried wolfphram alpha and it gave me an imaginary number???

Answer 10

Do you have a picture of the problem or something?

Answer 11

Ugh :( Ya that's not what you wrote out on top -_-

Answer 12

sorry i tried my best

Answer 13

Then Chris's derivative is correct :)
We just gotta be careful with the brackets.

Answer 14

P(t)=2*e^(-2e^(2t))

P'(t)=2e(-2e^(2t))*(-2)e^(2t)*2

Try that maybe? :d
Do you only get a limited number of "guesses"?

Answer 15

I'm on my last one, but oh well only got 3 mins left

Answer 16

oh XD

Answer 17

oops i made a typo :O hopefully you caught that. umm the first part of it

Answer 18

P'(t)=2e^(-2e^(2t))*(-2)e^(2t)*2

there we go,
forgot the carot on the first exponential >.<

Answer 19

carot hahaaha

Answer 20

caret* :3 i dunno, whatever this thing is called "^" hehe

Answer 21

oh haha it sorta looks like a carrot anyway

Answer 22

ouch lol was a second late, when i hit submit it turned to 12 am :(

Answer 23

automatically took me home

Answer 24

aw :P does it show solution?

Answer 25

lame t.t

Answer 26

it doesn't :(

Answer 27

im gonna get on it on office hours, thank guys!