Question

If a card is picked at random from a pack
of 52 cards. Find the probablity that it is
'a spade ' or 'a king' or 'a queen'?

Answer 1

\(\large \color{black}{\begin{align}
& \normalsize \text{ If a card is picked at random from a pack}\hspace{.33em}\\~\\
& \normalsize \text{ of 52 cards. Find the probablity that it is }\hspace{.33em}\\~\\
& \normalsize \text{ 'a spade ' or 'a king' or 'a queen'}\hspace{.33em}\\~\\
& a.)\ \dfrac{21}{52} \hspace{.33em}\\~\\
& b.)\ \dfrac{5}{13} \hspace{.33em}\\~\\
& c.)\ \dfrac{19}{52} \hspace{.33em}\\~\\
& d.)\ \dfrac{15}{52} \hspace{.33em}\\~\\
\end{align}}\)

Answer 2

add number of queen, king and spades cards divide by total number of cards

Answer 3

i think XD

Answer 4

P(A+B+C)=P(A+(B+C))=P(A)+P(B+C)-P(A)P(B+C)=P(A)+P(B)+P(C)-P(BC)-P(AB)-P(CA)+P(ABC)..
So P(A+B+C)=P(A)+P(B)+P(C)-P(AB)-P(BC)-P(CA)+P(ABC)

Answer 5

You need to use the above formula to solve this problem

Answer 6

i think
there are 13 spades
4 king
and 4 queen
4+4+13 /52 lol is this correct ?

Answer 7

oh okay nvm then..

Answer 8

Let A denote the event that a spade is picked, B denote the event that a king is picked and C denote the event that a queen is picked,,, then our required probability is P(A+B+C)

Answer 9

You must subtract cards in common.

Answer 10

P(A)=13/52=1/4
P(B)=4/52=1/13
P(C)=4/52=1/13
P(AB)=1/52
P(BC)=0
P(CA)=1/52
P(ABC)=0

Answer 11

13 spades, 3 kings which are not spades, 3 queens that are not spades

P(spade or king or queen) = 13/52 + 3/52 + 3/52 =

Answer 12

spade: 13 cards (including a king of spades and a queen of spades)
king: 3 cards (other than king of spades already counted above)
queen: 3 cards (other than queen of spades already counted above)
Total number of cards of interest: 13 + 3 + 3 = 19
Total number of cards in deck: 52
P(spade or king or queen) = 19/52

Answer 13

Now just plug in and you will get required probability=(1/4)+(1/13)+(1/13)-(1/52)-(1/52)
=(13+4+4-1-1)/52=19/52

Answer 14

i like that formula i forgot of p(a+b+c)

Answer 15

I derived the fomula , you may check

Answer 16

ah 3 king and 3 queens
lack of knowledge abt cards \,,/(>.<)\,,/ :D

Answer 17

I used google and it thinks that there is 4 queens , 4 kings.

Answer 18

@Nnesha

4 kings and 4 queens in the deck

3 kings and 3 queens in the deck are not spades.

See graphic below.

Answer 19

a spade ' or 'a king' or 'a queen ?
13, 4 , 4 ?

Answer 20

aw i see!
thanks i'll keep that n my mind..\o^_^o/