How many molecules are in 0.456mol of Al2(SO4)3

Question

photon336 · Answer

This is our molar mass. for aluminum sulfate. 


$$342.15 \frac{ g }{ mol } $$

but there's another rule and it says that 1 mol of any substance has: 

$$1 mol = (6.02x10^{23}particles)$$

set up a proportion, because if we know that this amount of particles is in 1 mol, then we need to find the number of particles in 0.456 moles of our sample. 

$$\frac{ 1 mol }{ 6.02x10^{23}particles } = \frac{ 0.456mol }{ x particles }$$

cross multiply, and we get. 

$$2.75x10^{23} particles $$

photon336 · Answer

@anabear127