discrete Math help :3.
construct the intersection of A1 = {0, 2, 4, 6, 8}, A2 = {0, 1, 2, 3, 4}, A3 = {1, 3, 5, 7, 9}, A4 = {5, 6, 7, 8, 9}, A5 = {0, 1, 8, 9}
gah damn
ik ; ;
praying for you, i take college leveled classes and i dont understand that ;-; praying for you
if you know how to solve it you dont have to answer it, just explain what its looking for :)
; ; this is a college class
i dont have that lol
for computer tech :P
required math :/
ouchhhh, hm well found this online so let me know what you think: Find the smallest relation containing the relation in Example 2 that is both reflexive and symmetric. Solution. Recall that R is a relation on N defined by (a, b) ∈ R if and only if a > b. To make R reflexive, we must add in all elements of the form (a, a), giving us R0, where (a, b) ∈ R0 if and only if a ≥ b. Now to make it symmetric, we must add in all elements of the form (a, b), where a ≥ b. This gives R00, where (a, b) ∈ R0” if and only if a ≤ b or a ≥ b. This includes all pairs (a, b) ∈ N2, so R00 = N2 is the smallest relation containing R that is both reflexive and symmetric.
hmm thanks :D, ill look into it but i think it helped... c:
yayyy you're welcome (: if you need anymore help, let me know
ok :3
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