Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

legendarynikki According to the diagram, what would be the measure of the angles in the second triangle if the angle given measures 48 degrees? Select one: a. 48 and 48 b. 60 and 72 c. 90 and 132 d. Not enough information given

OpenStudy (anonymous):

OpenStudy (johnweldon1993):

Well we can see these are similar triangles...it seems like the first one is 2 times bigger than the second *in terms of the sides* however the angles will remain the same By solving for the third side in both cases using the law of cosines, and then using the law of sines, we can find out the angles

OpenStudy (johnweldon1993):

Oops sorry, *the second is twice as big as the first* everything else is fine :)

OpenStudy (anonymous):

it not enough info right

undeadknight26 (undeadknight26):

Two names because one wasn't enough lel

undeadknight26 (undeadknight26):

And no there is enough info...@johnweldon1993 just told ye that

Directrix (directrix):

Indeed, the triangles are similar - see attachment.

OpenStudy (johnweldon1993):

Right, and just by using: the law of cosines \(\large a^2 = b^2 + c^2 - 2bc\cos(A)\) and the law of sines \(\large \frac{sin(A)}{a} = \frac{sin(B)}{b} = \frac{sin(C)}{c}\) we can solve for what we need

Directrix (directrix):

Question: How do you know where the given angle is located? >>if the angle given measures 48 degrees

Directrix (directrix):

Corresponding angles of similar triangles are congruent. Do you think that of the options, any two angles that along with 48 sum to 180 would be a correct answer?

Directrix (directrix):

I would be tempted to go for this: b. 60 and 72 but I would like to see where the given angle is located.

OpenStudy (johnweldon1993):

I'm assuming |dw:1444772655057:dw|

Directrix (directrix):

@johnweldon1993 What are you saying is the answer to the question?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!