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If f(x) = -x - 2 and g(x) = x^2, what is (g º f)(-6)?
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Know where to start with this?
I think you substitute things, but honestly I have no clue.
You're trying to find \(g(f(x))\) when \(x=-6\) Start with finding what \(g(-x-2)\) is first. that means in your function for \(g(x)\) you plug in \(-x-2\) wherever you see an \(x\)
once you expand that out, plug in the value of \(-6\) for \(x\) and simplify your equation.
alternatively, find \(g(-6)\) and then take \(f\) of the result
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Ok, so what happens when you expand \((-x-2)^2\) ?
You get -x - 4 ?
Not quite :( let's try this. \[(-x)^2 -2(-x)(4) +(4)^2\] whats that give you? :)
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