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Mathematics 12 Online
OpenStudy (leahhhmorgannn):

Geometric proofs help? http://prntscr.com/8r2fqn Which statement below completes Anastasia's proof? In triangle ADC and BCD, AB = DC (opposite sides of a rectangle are congruent) In triangle ADC and BCD, AB = DC (opposite sides of a rectangle are parallel) In triangle ADC and BCD, AD = BC (opposite sides of a rectangle are congruent) In triangle ADC and BCD, AD = BC (opposite sides of a rectangle are parallel)

OpenStudy (ybarrap):

You need a statement analogous to Statement 2 relating AD to BC. This allows the proof to proceed to Statement 3, using Pythagoras Theorem, to establish that \(AC^2=DB^2\). So how are AD and BC related? Use the same rational as Statement 2.

OpenStudy (leahhhmorgannn):

Our lesson hasn't taught us how to use the Pythagorean Theorem yet, but I tried to figure it out prior to asking on here and I put D... I don't think it's right though.

OpenStudy (leahhhmorgannn):

Answer A is like the exact copy of Statement 2, right?

jimthompson5910 (jim_thompson5910):

`opposite sides of a rectangle are parallel` isn't a proper justification of AD = BC

OpenStudy (leahhhmorgannn):

I only put that because our resource worksheet says that opposite sides of a rectangle are congruent and parallel for properties of rectangles, but I guess it doesn't really make sense. So, if we have to use the same logic/rational as in Statement 2, would it be C? sorry - I just really don't understand these.

jimthompson5910 (jim_thompson5910):

yes it should be `AD = BC (opposite sides of a rectangle are congruent)`

jimthompson5910 (jim_thompson5910):

it is true that the opposite sides of a rectangle are parallel but that fact isn't useful in this case

OpenStudy (leahhhmorgannn):

Okay, thanks so much for helping make sense of this.

jimthompson5910 (jim_thompson5910):

no problem

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