Geometry
15 Online
OpenStudy (anonymous):
what is the length of the altitude of the equilateral triangle below? (picture below)
a.240
b.4
c.12/3
d.4/3
e.144
f.12
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OpenStudy (anonymous):
OpenStudy (freckles):
use pythagorean theorem
OpenStudy (freckles):
solve for a (a>0):
\[(4 \sqrt{3})^2+a^2=(8 \sqrt{3})^2 \]
OpenStudy (anonymous):
am i suppose to square root 3?
OpenStudy (freckles):
there is no point because you are squaring the (square root of 3)
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OpenStudy (freckles):
example:
\[(4 \sqrt{3})^2 =4^2 (\sqrt{3})^2=16(3)\]
OpenStudy (anonymous):
so i multiply 4x3?
OpenStudy (anonymous):
please i need help :(
OpenStudy (freckles):
what part do you need help on?
OpenStudy (anonymous):
the pythagorean theorem
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OpenStudy (anonymous):
am i suppose to multiply 4 to 3?
OpenStudy (freckles):
is my math code not showing up?
I thought this answered this question:
"example:
\[(4 \sqrt{3})^2 =4^2 (\sqrt{3})^2=16(3)\]
"
OpenStudy (freckles):
you multiply 4^2 and 3
or aka 16 and 3
OpenStudy (freckles):
you try doing the other one:
\[(8 \sqrt{3})^2=?\]
OpenStudy (anonymous):
so i multiply 16 to 3 and 4x4? then after that i multiply them both together
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OpenStudy (anonymous):
i'm trying to solve for a
OpenStudy (freckles):
very good
we are simplifying right now
OpenStudy (anonymous):
so from 48 do i square root it?
OpenStudy (freckles):
why sqrt it?
OpenStudy (freckles):
there is no square root around it...
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OpenStudy (anonymous):
how do i simplify 48?
OpenStudy (freckles):
\[(4 \sqrt{3})^2+a^2=(8 \sqrt{3})^2 \\ 48+a^2=(8 \sqrt{3})^2 \]
can you try simplifying the right hand side
OpenStudy (freckles):
48 is as simple as 48 gets
OpenStudy (anonymous):
how do i simplify the right hand? Well then the answer is not 48?
OpenStudy (freckles):
no but that is what (4*sqrt(3))^2 equals
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OpenStudy (freckles):
you seen how applied law of exponents to simplify (4*sqrt(3))^2
you try doing it to (8*sqrt(3))^2
OpenStudy (anonymous):
so i multiply 8 x 8 which is 64 then i multiply the 64 to the 3?
OpenStudy (freckles):
yes
OpenStudy (anonymous):
so i got 192 what is next?
OpenStudy (freckles):
\[(4 \sqrt{3})^2+a^2=(8 \sqrt{3})^2 \\ 48+a^2=(8 \sqrt{3})^2 \\ 48+a^2=192 \text{ solve for } a^2 \text{ first }\]
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OpenStudy (anonymous):
is my answer c?
OpenStudy (freckles):
we will see
can you solve for a^2
OpenStudy (anonymous):
i got 12?
OpenStudy (freckles):
for a^2?
OpenStudy (freckles):
a^2=192-48
a^2=what is 192-48
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OpenStudy (anonymous):
yes
i plug in 48-192 which gave me 146 then I square rooted 146 and it came out as 12.08
OpenStudy (freckles):
192-48 isn't the same as 48-192
and also 192-48 isn't 146
OpenStudy (anonymous):
i still got 12 i subtracted wrong
OpenStudy (freckles):
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