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Geometry 15 Online
OpenStudy (anonymous):

what is the length of the altitude of the equilateral triangle below? (picture below) a.240 b.4 c.12/3 d.4/3 e.144 f.12

OpenStudy (anonymous):

OpenStudy (freckles):

use pythagorean theorem

OpenStudy (freckles):

solve for a (a>0): \[(4 \sqrt{3})^2+a^2=(8 \sqrt{3})^2 \]

OpenStudy (anonymous):

am i suppose to square root 3?

OpenStudy (freckles):

there is no point because you are squaring the (square root of 3)

OpenStudy (freckles):

example: \[(4 \sqrt{3})^2 =4^2 (\sqrt{3})^2=16(3)\]

OpenStudy (anonymous):

so i multiply 4x3?

OpenStudy (anonymous):

please i need help :(

OpenStudy (freckles):

what part do you need help on?

OpenStudy (anonymous):

the pythagorean theorem

OpenStudy (anonymous):

am i suppose to multiply 4 to 3?

OpenStudy (freckles):

is my math code not showing up? I thought this answered this question: "example: \[(4 \sqrt{3})^2 =4^2 (\sqrt{3})^2=16(3)\] "

OpenStudy (freckles):

you multiply 4^2 and 3 or aka 16 and 3

OpenStudy (freckles):

you try doing the other one: \[(8 \sqrt{3})^2=?\]

OpenStudy (anonymous):

so i multiply 16 to 3 and 4x4? then after that i multiply them both together

OpenStudy (anonymous):

i'm trying to solve for a

OpenStudy (freckles):

very good we are simplifying right now

OpenStudy (anonymous):

so from 48 do i square root it?

OpenStudy (freckles):

why sqrt it?

OpenStudy (freckles):

there is no square root around it...

OpenStudy (anonymous):

how do i simplify 48?

OpenStudy (freckles):

\[(4 \sqrt{3})^2+a^2=(8 \sqrt{3})^2 \\ 48+a^2=(8 \sqrt{3})^2 \] can you try simplifying the right hand side

OpenStudy (freckles):

48 is as simple as 48 gets

OpenStudy (anonymous):

how do i simplify the right hand? Well then the answer is not 48?

OpenStudy (freckles):

no but that is what (4*sqrt(3))^2 equals

OpenStudy (freckles):

you seen how applied law of exponents to simplify (4*sqrt(3))^2 you try doing it to (8*sqrt(3))^2

OpenStudy (anonymous):

so i multiply 8 x 8 which is 64 then i multiply the 64 to the 3?

OpenStudy (freckles):

yes

OpenStudy (anonymous):

so i got 192 what is next?

OpenStudy (freckles):

\[(4 \sqrt{3})^2+a^2=(8 \sqrt{3})^2 \\ 48+a^2=(8 \sqrt{3})^2 \\ 48+a^2=192 \text{ solve for } a^2 \text{ first }\]

OpenStudy (anonymous):

is my answer c?

OpenStudy (freckles):

we will see can you solve for a^2

OpenStudy (anonymous):

i got 12?

OpenStudy (freckles):

for a^2?

OpenStudy (freckles):

a^2=192-48 a^2=what is 192-48

OpenStudy (anonymous):

yes i plug in 48-192 which gave me 146 then I square rooted 146 and it came out as 12.08

OpenStudy (freckles):

192-48 isn't the same as 48-192 and also 192-48 isn't 146

OpenStudy (anonymous):

i still got 12 i subtracted wrong

OpenStudy (freckles):

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