Question

A quick probability question

Answer 1

sure

Answer 2

Find the probability that a randomly selected point will be in the shaded region.

Answer 3

what lesson is this?

Answer 4

I can help

Answer 5

Its not with connections, it with a different school

Answer 6

give it a go jango, im all ears

Answer 7

Suppose the length of each side of the square be a units. Then can you guess what is the area of the shaded portion?

Answer 8

The shaded region can be rearranged into a circle..

Answer 9

and the radius of the circle is half the length of each side of the square

Answer 10

hence radius of circle =(a/2) .
Required probability = area of circle/area of square = pi.(a/2)^2/a^2=pi/4

Answer 11

It doesn't give any sense of length or anything like that, and thats what throws me off

Answer 12

You will have to assume that the length of each side of the square is a units.

Answer 13

uhm..

Answer 14

Did you get the part that the radius is a/2?

Answer 15

im gonna take a wild guess here and say it would be 60% probability.
And so the circle would be half the square (a)???

Answer 16

i mean the radius would be half the square? or..

Answer 17

no wait.. First tell me did you get the part that the shaded region can be rearranged into a circle?

Answer 18

I believe you told me that, but yes the semicircles can be rearranged into s full circle inside the square

Answer 19

Yeah correct... Now the diameter of the circle is equal to the length of each side of the square so diameter=a and hence radius =diameter/2=a/2

Answer 20

okay..

Answer 21

Now the area of circle= pi r^2 where r is the radius and the area of a square of length a is a^2. our required probability= area of circle/ area of square

Answer 22

Do you want to write the solution of this problem? Then I write everything in a single attachment

Answer 23

I dont know the solution to the problem lol i know the area of a circle and the area of a square but i dont understand how to plug those formulas in without numbers lol its really confusing

Answer 24

THe unknown term a will eventually cancel out

Answer 25

and you will get the probability as pi/4

Answer 26

\[\pi(\frac{a }{ 2 })^{2}/a^2=\pi/2^2=\pi/4\]

Answer 27

uhm.. okay. i get that

Answer 28

If you have any problem let me know

Answer 29

im just gonna give up and guess because i really dont understand how to find the probability out of this equation.