Question

Simplify. Write each answer in standard form.
12. (2v^3 - v + 8) + (-v^3 + v - 3) =

14. (4h^3 + 3h + 1) - (-5h^3 + 6h - 2) =

Answer 1

@Michele_Laino

Answer 2

@carsonce

Answer 3

question #12
we can rewrite your expression as below:
\[\begin{gathered}
(2{v^3} - v + 8) + ( - {v^3} + v - 3) = \hfill \\
\hfill \\
= 2{v^3} - v + 8 - {v^3} + v - 3 = ... \hfill \\
\end{gathered} \]
plese combine similar terms

Answer 4

please*

Answer 5

@Michele_Laino 2v^3 - 2v + 8 - v^3 - 3 ?

Answer 6

we have:
\[\begin{gathered}
(2{v^3} - v + 8) + ( - {v^3} + v - 3) = \hfill \\
\hfill \\
= 2{v^3} - v + 8 - {v^3} + v - 3 = \hfill \\
\hfill \\
= {v^3}\left( {2 - 1} \right) + 8 - 3 + v\left( {1 - 1} \right) = ... \hfill \\
\end{gathered} \]

Answer 7

I have collected similar terms

Answer 8

I'm confused can you talk me threw it. And is v^3 (2-1) + 8-3 + v (1-1) the answer?

Answer 9

it is not the answer, it is the expression after I have collected similar terms.
Now:
what is 2-1=...?
8-3=...?
and 1-1=...?

Answer 10

hint:
we have:
\[\begin{gathered}
(2{v^3} - v + 8) + ( - {v^3} + v - 3) = \hfill \\
\hfill \\
= 2{v^3} - v + 8 - {v^3} + v - 3 = \hfill \\
\hfill \\
= {v^3}\left( {2 - 1} \right) + 8 - 3 + v\left( {1 - 1} \right) = ... \hfill \\
\hfill \\
= {v^3} + 5 \hfill \\
\end{gathered} \]

Answer 11

since 2-1=1 so we have 1*v^3
1-1=0, so there is not the term proportional to v
finally we have:
8-3=5

Answer 12

question 14)
here we have to eliminate the parentheses, so we have to flip the sign for each term inside the second parenthesis, so we can write this:
\[\begin{gathered}
(4{h^3} + 3h + 1) - ( - 5{h^3} + 6h - 2) = \hfill \\
\hfill \\
= 4{h^3} + 3h + 1 + 5{h^3} - 6h + 2 = ...? \hfill \\
\end{gathered} \]

Answer 13

I'm not sure how to solve questions 14 either. It doesn't make sense to me.

Answer 14

please add similar terms again

Answer 15

what is 4+5=...?

Answer 16

9h^3 - 3h + 3 ? Is that correct

Answer 17

correct!

Answer 18

it is the same procedure that I have applied to the first question

Answer 19

Okay can you help me with a few more?

Answer 20

I'm sorry, I'm receiving several requests for help, so please wait