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Mathematics 19 Online
OpenStudy (anonymous):

Let's say that I was given the population formula: P(t) = 2546e^(6t) where t is in years since 1986. How would I find the rate of change with this given formula?

OpenStudy (anonymous):

The derivative which is 15276e^(6t) right? I was not given r in the problem.

OpenStudy (freckles):

oh okay I was doing growth rates or whatever it was called above

OpenStudy (freckles):

\[P(t)=ae^{bt} \\ \implies P'(t)=a \cdot be^{bt}\]

OpenStudy (freckles):

yes 6*2546 is 15276

OpenStudy (freckles):

your derivative is right

OpenStudy (freckles):

did you want to find the rate of change at a certain number you just use the derivative there...

OpenStudy (freckles):

or if you wanted to find an average rate of change that is a little different

OpenStudy (anonymous):

Alright, thanks for the clarifications!

OpenStudy (freckles):

\[\text{ average rate of change from } x=a \text{ to } x=b \\ \text{ would be } \frac{P(b)-P(a)}{b-a}\]

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