Question

Simplify each product. Write in standard form.
18. 6g^2 (g - 8) =

20. -2n^2 (5n - 9 + 4n^2) =

Answer 1

@Michele_Laino

Answer 2

u know the way to solve it?

Answer 3

@ArifL Not really. I need someone to talk me threw it.

Answer 4

just multiply the outer number to each one inside

Answer 5

@Nnesha

Answer 6

@ArifL Can you show me please so I can understand?

Answer 7

@carsonce

Answer 8

Yes?

Answer 9

@carsonce Can you help me please?

Answer 10

\[6g ^{2}(g-8) \]\[(6g ^{2}\times g)+(6g ^{2}\times-8)\]

Answer 11

There you go ^

Answer 12

@ArifL Can you explain to me how you got that answer? And is (6g^2 times g) + (6g^2 times -8) the answer?

Answer 13

no, it not the answer

Answer 14

it the first step

Answer 15

So what is the next step?

Answer 16

just finish it

Answer 17

@phi

Answer 18

@ArifL 12g^2 + (-8) is that correct?

Answer 19

yeah, sorry im not that good at teaching

Answer 20

no it 6g^3-48g^2

Answer 21

Can you explain to me how that is the answer?

Answer 22

How is it 6g^3 ? How does the exponent change?

Answer 23

\[a ^x \times a^y= a ^{x+y}\]

Answer 24

it just count if it is the same variable

Answer 25

@ArifL If you're adding the exponents shouldn't it be 6g^4 ?

Answer 26

\[6g^2\times g^1\]

Answer 27

\(\color{blue}{\text{Originally Posted by}}\) @ArifL
\[a ^x \times a^y= a ^{x+y}\]
\(\color{blue}{\text{End of Quote}}\)
look at the exponent rule provided by arifl
when we multiply same bases we should `add` their exponents

Answer 28

6g^2 (g - 8)
= (6g^2 times g) + (6g^2 times -8)
= 6g^3 - 48g^2 is that in standard form?

Answer 29

yep

Answer 30

just that is good

Answer 31

how would i explain it, u just need to multiply it

Answer 32

@MrNood can u help us?

Answer 33

@Nnesha can u help us again?

Answer 34

yes ?

Answer 35

it's distributive property
multiply each term in the parentheses by outside ter m

Answer 36

@Nnesha THANK YOU!!

Answer 37

hmm yw??

Answer 38

just like arif mentioned
multiply each term by outside term :=))