Question

Review: 2D Forces

Question below

Answer 1

@MrNood

Answer 2

@Michele_Laino

Answer 3

@Vincent-Lyon.Fr

Answer 4

on your cable are acting three forces, namely the weight force of the block, and the forces exerted by points A and B:

the equilibrium condition is given by the subsequent vector equation:
\[{\mathbf{P + }}{{\mathbf{F}}_{\mathbf{1}}}{\mathbf{ + }}{{\mathbf{F}}_{\mathbf{2}}}{\mathbf{ = 0}}\]

Answer 5

ok, understand that.

Answer 6

I also have to find the tension for BD.

Answer 7

by argument of symmetry we can assume the subsequent relationship between F1 and F2:
\[\left| {{{\mathbf{F}}_{\mathbf{1}}}} \right| = \left| {{{\mathbf{F}}_{\mathbf{2}}}} \right|\]
namely the magnitude of F1 is equal to the magnitude of the vector F2

Answer 8

I don't think so because the right answer on the book says: \(\sf F_{AB}=29.4 kN,\ F_{BC}=15.2kN,\ F_{BD}=21.5 kN\)

Answer 9

I don't know how they got those values

Answer 10

so F1 anf F2 are not equal ?

Answer 11

you are right, I see, your system is not symmetric

Answer 12

i'm not sure how to do it :/

Answer 13

ok! so we cancel the relationship \[\left| {{{\mathbf{F}}_{\mathbf{1}}}} \right| = \left| {{{\mathbf{F}}_{\mathbf{2}}}} \right|\]

Answer 14

the subsequent formula still holds:
\[{\mathbf{P + }}{{\mathbf{F}}_{\mathbf{1}}}{\mathbf{ + }}{{\mathbf{F}}_{\mathbf{2}}}{\mathbf{ = 0}}\]

Answer 15

we have to establish a system of coordinate as below: