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how many atoms are in 80.45g of magnesium?
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Convert mass to moles (divide by molar mass), then convert moles to number of atoms (multiply by Avogadro's number).
There is one mol per 24.305g of Mg.: \(80.45/24.305=??\) Once you know the moles of the sample you can use Avagadro's number to find the number of atoms. \(6.02× 10^23 × (??)=\)_______\(×10^24\) atoms of Mg @hype.child Solving, how much you got ?
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