if 294 grams of FeS2 is allowed ti react with 176 grams of O2 according to the following equation how many grams of Fe2O3 are produced?

FeS2 + O2 = Fe2O3 + SO2

Question

if 294 grams of FeS2 is allowed ti react with 176 grams of O2 according to the following equation how many grams of Fe2O3 are produced?

FeS2 + O2 = Fe2O3 + SO2

koikkara · Answer

@ayat7654 Now, it's your turn... Solve it, then i'll help you when u get stuck.

anonymous · Answer

@koikkara
:)
I hope it's 👍🏻

koikkara · Answer

Nope, wrong... You hav to balance the eqn first and then start with it....
                                             $FeS2 + O2 = Fe2O3 + SO2 $
Balanced Eqn: 
                                            $4 FeS2 + 11 O2 = 2 Fe2O3 + 8 SO2$
Substituting values,
           $294g.FeS2× 1mol.FeS2/119.99× 11mols .O2/4mols .FeS2$ $= 6.738mol .O2$ 
            $176gO2×1mol O2/32gO2× 4mols FeS2/11mol FeS2$$= 2mols FeS2 $

select, molecule with the lowest amount (Limiting Reagent) 
             $2molsFeS2×2molsFe2O3/4molsFeS2×159.7gF$... 
                         $159.7g. Fe2O3( grams) produced$

@ayat7654

anonymous · Answer

@koikkara

anonymous · Answer

@koikkara 
Oh..by mistake 
But thanks