how do you find the distance between two points using thee Pythagorean theorem?
draw a right triangle
|dw:1444862017826:dw|
|dw:1444862036490:dw|
then use the Pythagorean theorem to find c (which is the distance between the two points) a^2 + b^2 = c^2
\[x ^{2}+y ^{2}= distance ^{2}\]
thanks guys so much, and any one who else wants to answer it feel free lol
the distance between your X's squared plus the distance between your Y's squared will give you the distance between the points squared.
(x2-x1)^2 +(y2-y1)^2 = distance^2
@Hyroko so for x2 and y2 could that be a2 nd y2?
First point (x1,y1) Second point (x2,y2)
so x2-x1 will give you the distance between the points on the X axis and y2-y1 will give you the distance between the points on the Y axis. then you square those values. then add them together. then take the square root of your answer and you have the distance between the 2 points.
http://learn.flvs.net/educator/common/Pre-algebraPatCarlisle/PreAlgv16Module3DBA.jpg
for example, if you had a point (0,5) and the point (5,6) 5-0 = 5 6-5 = 1 (5)^2 + (1)^2 = 26 the distance would be \[\sqrt{26}\]
just realized that may be a bad example.... Lol (3,4) (5,6) 5-3 = 2 6-4 = 2 (2)^2+(2)^2 = 8 distance is \[\sqrt{8}\]
thanks so much @Hyroko
Join our real-time social learning platform and learn together with your friends!