please help me, can't find the answer anywhere. f^-1(3) if f(x)=3x+ln x I need to find a fractional solution. I think it's 4/5 or something like that, but I'm not sure. If anyone here is adept at Pre-Calculus please respond.
You want to solve \(x\) in : \(3 = 3x+\ln x\)
your job is to solve \[3x+\ln(x)=3\]
don't try algebra do it "by inspection"
am I supposed to try different numbers in the place of x until I find it?
i.e guess at a solution make an educated guess you cannot solve this using algebra because you have both \(3x\) and \(\ln(x)\) make a guess i bet you get it on the first or second try
hint, start with the smallest positive integer
there is a very natural number to try usually your teacher makes it easy for you to guess, give it a try..
this is what I have so far. 3=x+e^3
as @satellite73 said, you'll probably get it on your \(\large \text{first}\) try
1 works, but he said that's not the answer he's looking for.
no you are trying to manipulate it (incorrectly) at the risk of repeating myself don't be shy, give it a try
really?
x = 1 is the only solution
yeah, he wants us to solve it and apparently you can find a fractional answer
cause there aint another one
he handed out a multiple choice quiz last week with this question and I guessed it, but it's coming up on the test soon and I want to figure it out before. all of the options were fractions.
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