Let f (x)=x^3+px^2+qx. Find the values of p and q so that f (-1)=8 and f'(-1)=12

Question

anonymous · Answer

replace $x$ by $-1$ get an equation in $p$ and$q$

anonymous · Answer

take the derivative, replace $x$ by $-1$ get another equation in $p$ and $q$
then solve the system of equations

dayakar · Answer

f (x)=x^3+px^2+qx. Find the values of p and q so that f (-1)=8 and f'(-1)=12
f(-1)=8
$$\left( -1 \right)^{3}+p \times \left( -1 \right) ^{2}+q \times \left( -1 \right)=8$$

anonymous · Answer

the first equation is 
$$-1+p-q=8$$ or 
$$p-q=9$$ i will let you find the second one

dayakar · Answer

-1+p-q=8

anonymous · Answer

3-2p+q=12?

dayakar · Answer

f(-1) =8
f(-1)= 12
the problem is wrong

dayakar · Answer

both times you typed f(-1), verify

anonymous · Answer

Second one was sipped to be f'(-1)=12

anonymous · Answer

Dealing with derivatives on the first degree