Question

Let f (x)=x^3+px^2+qx. Find the values of p and q so that f (-1)=8 and f'(-1)=12

Answer 1

replace \(x\) by \(-1\) get an equation in \(p\) and\(q\)

Answer 2

take the derivative, replace \(x\) by \(-1\) get another equation in \(p\) and \(q\)
then solve the system of equations

Answer 3

f (x)=x^3+px^2+qx. Find the values of p and q so that f (-1)=8 and f'(-1)=12
f(-1)=8
\[\left( -1 \right)^{3}+p \times \left( -1 \right) ^{2}+q \times \left( -1 \right)=8\]

Answer 4

the first equation is
\[-1+p-q=8\] or
\[p-q=9\] i will let you find the second one

Answer 5

-1+p-q=8

Answer 6

3-2p+q=12?

Answer 7

f(-1) =8
f(-1)= 12
the problem is wrong

Answer 8

both times you typed f(-1), verify

Answer 9

Second one was sipped to be f'(-1)=12

Answer 10

Dealing with derivatives on the first degree