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OpenStudy (shelby1290):
Factor completely using the most appropriate method.
a) w^2-30-7w
b)24x-x^3-10x^2
c)9-(2x+3)^2
d)x^2 - 1/4
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OpenStudy (dayakar):
a)\[w^{2}+3w-10w-30\]
OpenStudy (dayakar):
w(w+3)-10(w+3)
OpenStudy (dayakar):
(w+3)(w-10)
OpenStudy (dayakar):
b)take -x common
OpenStudy (shelby1290):
for part A, how did you get 3 and -10?
i thought you were supposed to find two numbers that multiply to -7 and add up to -30
3 X -10=-30
3 + (-10) =-7
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OpenStudy (dayakar):
\[= -x(-24+x^{2}+10x)\]
OpenStudy (dayakar):
you are right
OpenStudy (dayakar):
\[=-x(x^{2}+10x-24)\]
OpenStudy (dayakar):
\[=-x(x^{2}-6x-4x+24)\]
OpenStudy (dayakar):
=-x[x(x-6)-4(x-6)
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OpenStudy (dayakar):
=-x[(x-6)(x-4)]
OpenStudy (dayakar):
are u following
OpenStudy (shelby1290):
yes i am
OpenStudy (dayakar):
c)\[=3 ^{2}-\left( 2x+3 \right){2}\]
OpenStudy (shelby1290):
for part C, do you have to use the foil method?
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OpenStudy (dayakar):
it in the form of
\[x^{2}-y^{2}=(x+y)(x-y)\]
OpenStudy (dayakar):
[(3+(2x+3)][3-(2x+3)]
OpenStudy (dayakar):
(3+2x+3)(3-2x-3)
OpenStudy (dayakar):
(6+2x)(-2x)
OpenStudy (dayakar):
take 2 as common
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OpenStudy (dayakar):
2(3+x)(-2x)
OpenStudy (dayakar):
=2(-2)x(x+3)
=-4x(x+3)
OpenStudy (dayakar):
is it clear
OpenStudy (shelby1290):
so -4x(x+3) is the final answer? in my book, the answer is (2x+6)(-2x)
OpenStudy (dayakar):
both are same ,i simplified further
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OpenStudy (dayakar):
ok
OpenStudy (dayakar):
d) is like above problem,can u try or may i help u
OpenStudy (shelby1290):
i'll try it and you can make sure that it's right
OpenStudy (dayakar):
good
OpenStudy (shelby1290):
|dw:1444879966874:dw|
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