Question

In a solution of 1.0E-4 M Cu+ and 2.0E-3 M Pb2+, what will precipitate if the concentration of I- is 5.0E-9 M?

Ksp CuI = 5.3E-12
Ksp PbI2 = 1.4E-8

A) CuI

B) PbI2

C) both

D) neither

Can you help me @matt101

Answer 1

It's due in like 10 minutes

Answer 2

Finish the other one first. Then use the same method for this guy.

Answer 3

i did ,i got the cation and molar solubility right, but still the anion was wrong

Answer 4

would it be B for this one?

Answer 5

The anion for the other one is just 3 times the molar solubility, because it is 3 times as concentrated.

Answer 6

oh...

Answer 7

if it's 3 times as concentrated that means the ksp is larger and the precipitate wil form there, so A?

Answer 8

I was referring to the other question you asked, about Cr(OH)3

Answer 9

Oh ok

Answer 10

For this question though, why did you choose B?

Answer 11

i did 3x^3 for the other anion.

Answer 12

I chose B because it seems like the concentration is larger and therefore the Ksp is larger than in A

Answer 13

For the other question, the concentration is JUST 3x. The cubing is something you do as part of the equation, but it is NOT a part of the concentration itself. Read my explanation back there carefully.

For this question, calculate Q for each solid. If Q > Ksp, the solid will precipitate. If Q is less than Ksp, the solid will not precipitate. What do you get?