Question

Please help

Answer 1

Identify the horizontal asymptote of f(x) = 3 over 5 x.

y = 3 over 5
y = 0
y = 5 over 3
No horizontal asymptote

Answer 2

@Nnesha

Answer 3

@HS_CA

Answer 4

Evaluate the following.

104

100,000
40
10,000
1,000

Answer 5

for\(\color{green}{\rm Horizontal ~asy.}\)
focus on highest degrees
~if the highest degree of the numerator is greater than the denominator then `No horizontal asy.` \[\color{reD}{\rm N}>\color{blue}{\rm D}\] example
\[\large\rm \frac{ 7x^\color{ReD}{3} +1}{ 4x^\color{blue}{2}+3 }\]
~if the highest degree of the denominator is greater than the highest degree of the numerator then `y=0` would be horizontal asy.
\[\rm \color{reD}{N}<\color{blue}{\rm D}\]
example:\[\large\rm \frac{ 7x^\color{red}{2}+1 }{ 4x^\color{blue}{3}+3 }\]
~if both degrees are the same then divide the leading coefficient of the numerator by the leading coefficient of the denominator
\[\rm \color{red}{N}=\color{blue}{D}\]\[\large\rm \frac{ 8x^\color{reD}{3}+1 }{ 4x^\color{blue}{3}+3 }\] \[\rm \frac{ 8x^3 }{ 4x^3 } =2\] horizontal asy. =2

Answer 6

looks long but there are few lines to read :=))

Answer 7

Evaluate the following.

104

100,000
40
10,000
1,000
help

Answer 8

let me know if you don't understand anything from that :=))

Answer 9

\[\huge\rm f(x)=\frac{3}{5x}\] is same as \[\huge\rm \frac{ 3x^0 }{ 5x }\]
anything to the zero power equal to one
that's how its just 3 in the equation
\[\large\rm \frac{ 3x^0 }{ 5x }\]
so which rule you should apply ?
what's the degree of the numerator and what's the degree of the denominator ?

Answer 10

very right

Answer 11

@phi