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Mathematics 14 Online
OpenStudy (gabylovesyou):

What value is added to both sides of the equation x2 − 2x = 10 in order to solve by completing the square? −2 −1 1 2

OpenStudy (gabylovesyou):

@freckles

OpenStudy (gabylovesyou):

@amistre64 @dan815

OpenStudy (amistre64):

what does it mean to complete a square?

OpenStudy (gabylovesyou):

ummmm i have no idea ... ._.

OpenStudy (zkoqmosii):

My math teacher's got a cool way to do this. Let me see if I can find a picture.

OpenStudy (zkoqmosii):

I'm pretty sure it'd be (-b/2a)^2

OpenStudy (amistre64):

hmm, well it means that we want to create a perfect square out of what we are given. say we are given the number 5, is it a perfect square? if not, then what would we add to it to complete the square?

OpenStudy (amistre64):

(a+b)^2 is a perfect square, it expands to a trinomial. can you expand it for me?

OpenStudy (gabylovesyou):

(a +b)(a+b) ?

OpenStudy (amistre64):

yes (a+b)(a+b) what does it look like when we expand it all out to a sum of 3 terms?

OpenStudy (gabylovesyou):

(a^2 + b)b ?

OpenStudy (gabylovesyou):

lol wait no.. idk .-.

OpenStudy (amistre64):

you are going to have to remember how to multiply 2 binomial expressions ... either foil it out or just distribute ... but i cant do it for you.

OpenStudy (gabylovesyou):

is it a^2 +2ab + b^2

OpenStudy (amistre64):

thats it :)

OpenStudy (gabylovesyou):

okok lol bad memory ._.

OpenStudy (amistre64):

now that form is a 'complete' square lets compare it to what we have a^2 + 2ab + b^2 x^2 -2x let a=x x^2 + 2b x + b^2 x^2 -2x when does -2x = 2b x? for what value of b?

OpenStudy (gabylovesyou):

-1 ?

OpenStudy (gabylovesyou):

idk if thats what u asked.

OpenStudy (amistre64):

yes, b=-1 now you should notice that in order to complete our square, we have to add b^2 to the setup .. what is (-1)^2 ?

OpenStudy (gabylovesyou):

1

OpenStudy (amistre64):

good x^2 - 2x + (-1)^2 x^2 -2x ^^^^ add this part to complete the square. so yes, add 1 to each side.

OpenStudy (gabylovesyou):

So answer is c.. thank you ^-^

OpenStudy (amistre64):

good luck :)

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