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OpenStudy (rainbow_rocks03):
OpenStudy (rainbow_rocks03):
ok
OpenStudy (rainbow_rocks03):
plz explain
OpenStudy (anonymous):
on the speed it goes up 10 every second
so for 1 second it goes 10 meters high
OpenStudy (rainbow_rocks03):
so my answer is 10 meters per second squared
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OpenStudy (anonymous):
i belive so
OpenStudy (rainbow_rocks03):
@zepdrix !!!!!!!!! @whpalmer4
OpenStudy (rainbow_rocks03):
@zepdrix !!!!!
OpenStudy (whpalmer4):
You are to find the proportionality constant. You have number of pairs of \((x,y)\) you can use.
\[y = kx\]
One such pair is \((1 \text{ second},10\text{ meters/second})\)
\[10 \text{ meters/second} = k(1\text{ second})\]\[k=10\text{ meters/second}^2\]
OpenStudy (rainbow_rocks03):
NM!
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OpenStudy (whpalmer4):
the proportionality constant here is the acceleration, which has units of the form \[[length]/[time]^{2}\]
OpenStudy (rainbow_rocks03):
YAH CAME TO LATE.
OpenStudy (whpalmer4):
If I get tagged on a question and feel like answering it, I answer it. Just because you may have found the answer doesn't mean that no one else will benefit.