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Mathematics 9 Online
OpenStudy (rainbow_rocks03):

PLZ HELP!!!!!

OpenStudy (rainbow_rocks03):

OpenStudy (rainbow_rocks03):

ok

OpenStudy (rainbow_rocks03):

plz explain

OpenStudy (anonymous):

on the speed it goes up 10 every second so for 1 second it goes 10 meters high

OpenStudy (rainbow_rocks03):

so my answer is 10 meters per second squared

OpenStudy (anonymous):

i belive so

OpenStudy (rainbow_rocks03):

@zepdrix !!!!!!!!! @whpalmer4

OpenStudy (rainbow_rocks03):

@zepdrix !!!!!

OpenStudy (whpalmer4):

You are to find the proportionality constant. You have number of pairs of \((x,y)\) you can use. \[y = kx\] One such pair is \((1 \text{ second},10\text{ meters/second})\) \[10 \text{ meters/second} = k(1\text{ second})\]\[k=10\text{ meters/second}^2\]

OpenStudy (rainbow_rocks03):

NM!

OpenStudy (whpalmer4):

the proportionality constant here is the acceleration, which has units of the form \[[length]/[time]^{2}\]

OpenStudy (rainbow_rocks03):

YAH CAME TO LATE.

OpenStudy (whpalmer4):

If I get tagged on a question and feel like answering it, I answer it. Just because you may have found the answer doesn't mean that no one else will benefit.

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