Simplify the expression as much as possible and make all exponents positive. (2a^-3b5)^4(8a^-5b^-6)^-2
\(\Large \left( 2a^{-3}b^5 \right)^4\left( 8a^{-5}b^{-6} \right)^{-2} ?\)
Yes
I have no idea how to go about this...
@jdoe0001
\(\bf \left( 2a^{-3}b^5 \right)^{\color{blue}{ 4}}\left( 8a^{-5}b^{-6} \right)^{{\color{brown}{ -2}}} \\ \quad \\ 2^{\color{blue}{ 4}}a^{-3\cdot {\color{blue}{ 4}}}b^{5\cdot {\color{blue}{ 4}}}8^{\color{brown}{ -2}}a^{-5\cdot {\color{brown}{ -2}}}b^{-6\cdot {\color{brown}{ -2}}} \\ \quad \\ 2^4a^{-12}b^{20}8^{-2}a^{10}b^{12} \\ \quad \\ 2^4\cdot 8^{-2}\cdot a^{-12}\cdot a^{10}\cdot b^{20}\cdot b^{12} \\ \quad \\ 2^4\cdot {\color{brown}{ \cfrac{1}{8^2} }}\cdot a^{-12}\cdot a^{10}\cdot b^{20}\cdot b^{12}\) and use the exponent rules, to combine the terms with the same base that is, "a" and "b"
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