Question

Convert the following binary number to decimal and hexadecimal assuming 16-bits for each number and two's complement representation for negative numbers: 11101001001111002

Answer 1

researching what i need to do here. if anyone wants to help that would be greatly appreciated! :)

Answer 2

@jim_thompson5910 :)

Answer 3

what is the binary number you talk about

Answer 4

or am I suppose to imagine that 2 at the end there is not there

Answer 5

binary numbers are numbers made up of only one's and zero's

Answer 6

that two is representing base two

Answer 7

example of converting binary to base 10:
\[11101=1 \cdot 2^4+1 \cdot 2^3+1 \cdot 2^2+0 \cdot 2^1+1 \cdot 2^{0}=8+4+1=29 \\ \\ \text{ so this means } 11101_2=29_{10} \\ \text{ hmm..,. maybe that 2 at the end is a subscript you have above }\]
anyways I usually convert to hexadecimal after converting to base 10...
\[29=1 \cdot 16^1+13 \cdot 16^0 \\ \text{ we need a letter for 13 } \\ 10=a\\ 11=b\\12=c\\ 13=d \\ 14=e \\ 15=f \\ \text{ so we have } 29_{10}=1d_{16}\]

Answer 8

i'm reading through this example. hold on

Answer 9

there is an easier way for bigger numbers for converting base 10 to whatever base...

Answer 10

@freckles cool, so i raise 2 to power how many digets are behind the number i'm looking at and add. what is with the 16bit and two's compliment about?

Answer 11

but let me choose a long example because it might be hard to see a pattern we just two steps...
say we wanted to write 29 in base 2...
we already know what it should look like from doing the above example: