x^3 - 125. How do I factor it? @jim_thompson5910
have you learned the difference of cubes rule?
The difference is when you subtract a cube
have you learned this formula? \[\Large a^3 - b^3 = (a-b)*(a^2+ab+b^2)\]
yes. I just learned it today.
ok you'll use this formula to factor
in this case, a = x and b = 5 since 5^3 = 125
ok. I got x(x^2-5)(x+25) as the answer.
\[\Large a^3 - b^3 = (a-b)*(a^2+ab+b^2)\] \[\Large x^3 - 5^3 = (x-5)*(x^2+x*5+5^2)\] \[\Large x^3 - 5^3 = (x-5)*(x^2+5x+25)\] \[\Large x^3 - 125 = (x-5)*(x^2+5x+25)\]
I think you have to simplify after you fill in the pattern.
that's as simplified as it gets
we cannot factor `x^2 + 5x + 25`
Never mind, because in some problems you have to simplify.
if b was 10x we can factor.
I'm not sure what you mean
x^2 + 10x + 25 = (x+5)(x+5). it only works if there was a ten.
oh I see, well if b = 10, then b^2 would be 100 so that 25 would change to 100
The problem is not fair.
Join our real-time social learning platform and learn together with your friends!