Mathematics
20 Online
OpenStudy (pulsified333):
Help please
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OpenStudy (anonymous):
ok
OpenStudy (pulsified333):
What did i do wrong?
OpenStudy (pulsified333):
@satellite73
OpenStudy (anonymous):
hmm
OpenStudy (anonymous):
this is going to take a second
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OpenStudy (pulsified333):
okay i am curious as to what i did wrong because i thought what i did was right
OpenStudy (anonymous):
three red
two red, one green
two green one red
three green
OpenStudy (pulsified333):
i did that
OpenStudy (anonymous):
\[P(3 red)=\frac{\binom{6}{3}}{\binom{14}{3}}=\frac{5}{91}\]
OpenStudy (pulsified333):
i got that for 3 red
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OpenStudy (anonymous):
red pays off 50 cents so you get \(1.50-1.40=.10\) a dime
OpenStudy (pulsified333):
i got that as well
OpenStudy (anonymous):
is that the last one?
OpenStudy (anonymous):
the one you got right?
OpenStudy (pulsified333):
yeah, basically I only got 3 red right, everything else is wrong
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OpenStudy (anonymous):
ok lets do 3 green your first one i guess
OpenStudy (pulsified333):
i see one mistake already
OpenStudy (pulsified333):
for 3 green i put 20/364 when on my work it says 56/364
OpenStudy (anonymous):
\[P(3 green)=\frac{\binom{8}{3}}{\binom{14}{3}}=\frac{2}{13}\]
OpenStudy (anonymous):
you get \(.60\) for a loss of \(-.80\)
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OpenStudy (anonymous):
so if that is the first one, both numbers are wrong
OpenStudy (pulsified333):
oh
OpenStudy (anonymous):
not sure how you got \(-.9\)
OpenStudy (anonymous):
i bet you can do the rest
i have to go have a whiskey
good luck
OpenStudy (pulsified333):
okay thanks