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Mathematics 20 Online
OpenStudy (pulsified333):

Help please

OpenStudy (anonymous):

ok

OpenStudy (pulsified333):

What did i do wrong?

OpenStudy (pulsified333):

@satellite73

OpenStudy (anonymous):

hmm

OpenStudy (anonymous):

this is going to take a second

OpenStudy (pulsified333):

okay i am curious as to what i did wrong because i thought what i did was right

OpenStudy (anonymous):

three red two red, one green two green one red three green

OpenStudy (pulsified333):

i did that

OpenStudy (anonymous):

\[P(3 red)=\frac{\binom{6}{3}}{\binom{14}{3}}=\frac{5}{91}\]

OpenStudy (pulsified333):

i got that for 3 red

OpenStudy (anonymous):

red pays off 50 cents so you get \(1.50-1.40=.10\) a dime

OpenStudy (pulsified333):

i got that as well

OpenStudy (anonymous):

is that the last one?

OpenStudy (anonymous):

the one you got right?

OpenStudy (pulsified333):

yeah, basically I only got 3 red right, everything else is wrong

OpenStudy (anonymous):

ok lets do 3 green your first one i guess

OpenStudy (pulsified333):

i see one mistake already

OpenStudy (pulsified333):

for 3 green i put 20/364 when on my work it says 56/364

OpenStudy (anonymous):

\[P(3 green)=\frac{\binom{8}{3}}{\binom{14}{3}}=\frac{2}{13}\]

OpenStudy (anonymous):

you get \(.60\) for a loss of \(-.80\)

OpenStudy (anonymous):

so if that is the first one, both numbers are wrong

OpenStudy (pulsified333):

oh

OpenStudy (anonymous):

not sure how you got \(-.9\)

OpenStudy (anonymous):

i bet you can do the rest i have to go have a whiskey good luck

OpenStudy (pulsified333):

okay thanks

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